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Question: The equation of the common tangent touching the circle (x – 3)<sup>2</sup> + y<sup>2</sup> = 9 and ...

The equation of the common tangent touching the circle

(x – 3)2 + y2 = 9 and the parabola y2 = 4x above the x-axis is –

A

3\sqrt{3}y = 3x + 1

B

3\sqrt{3}y = –(x + 3)

C

3\sqrt{3}y = x + 3

D

3\sqrt{3}y = – (3x + 1)

Answer

3\sqrt{3}y = x + 3

Explanation

Solution

(x – 3)2 + y2 = 9 ....(1)

̃ C1(3, 0); r1 = 3

y2 = 4x ...(2) ̃ 4a = 4 ̃ a = 1

equation of tangent of parabola (2) is

̃ y = mx + a/m ̃ y = mx + 1/m

̃ m2x – my + 1 = 0 ...(3)

̃ C1N = r1 ̃ m = ? put in (3)