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Question

Question: The equation of the common tangent to the parabolas y<sup>2</sup> = 32x and x<sup>2</sup> = 108y is...

The equation of the common tangent to the parabolas y2 = 32x and x2 = 108y is

A

2x+3y+36=02x + 3y + 36 = 0

B

3x+2y+108=03x + 2y + 108 = 0

C

3x+2y36=03x + 2y - 36 = 0

D

2x+3y108=02x + 3y - 108 = 0

Answer

2x+3y+36=02x + 3y + 36 = 0

Explanation

Solution

The equation of the common tangent to two parabolas

y2 = 4ax and x2 = 4by isa1/3x+b1/3y+a2/3b2/3=0a^{1/3}x + b^{1/3}y + a^{2/3}b^{2/3} = 0.

∴ The common tangent to the given parabolas is

2x+3y+36 = 0.