Question

The equation of the circumcircle of the triangle formed by the lines $y + \sqrt { 3 } x = 6 , y - \sqrt { 3 } x = 6$ and $y = 0$ , is.

• A. $x ^ { 2 } + y ^ { 2 } - 4 y = 0$
• B. $x ^ { 2 } + y ^ { 2 } + 4 x = 0$
• C. $x ^ { 2 } + y ^ { 2 } - 4 y = 12$
• D. $x ^ { 2 } + y ^ { 2 } + 4 x = 12$

Answer 1

Answer: (C)

$x ^ { 2 } + y ^ { 2 } - 4 y = 12$

Answer 2

Solving $y = 0$ and $y + \sqrt { 3 } x = 6$ , we get $( 2 \sqrt { 3 } , 0 )$, only option (3) satisfies the co-ordinate.