Question
Question: The equation of the circle with centre on x-axis, radius 5 and passing through the point (2, 3), is....
The equation of the circle with centre on x-axis, radius 5 and passing through the point (2, 3), is.
A
x2+y2+4x−21=0
B
x2+y2+4x+21=0
C
x2+y2−4x−21=0
D
x2+y2+5x−21=0
Answer
x2+y2+4x−21=0
Explanation
Solution
Let centre be (−g,0), then g2−c=5⇒c=g2−25
Also it passes through (2, 3), therefore
13+4g+g2−25=0⇒g=−6,2
Hence the equations are x2+y2−12x+11=0 and
x2+y2+4x−21=0.