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Question

Question: The equation of the circle with centre on the x-axis, radius 4 and passing through the origin, is....

The equation of the circle with centre on the x-axis, radius 4 and passing through the origin, is.

A

x2+y2+4x=0x ^ { 2 } + y ^ { 2 } + 4 x = 0

B

x2+y28y=0x ^ { 2 } + y ^ { 2 } - 8 y = 0

C

x2+y2±8x=0x ^ { 2 } + y ^ { 2 } \pm 8 x = 0

D

x2+y2+8y=0x ^ { 2 } + y ^ { 2 } + 8 y = 0

Answer

x2+y2±8x=0x ^ { 2 } + y ^ { 2 } \pm 8 x = 0

Explanation

Solution

As the centre may be (±4,0)( \pm 4,0 ) and radius = 4.