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Question

Question: The equation of the circle whose diameters have the end points (a, 0) (0, b) is given by....

The equation of the circle whose diameters have the end points (a, 0) (0, b) is given by.

A

x2+y2axby=0x ^ { 2 } + y ^ { 2 } - a x - b y = 0

B

x2+y2+axby=0x ^ { 2 } + y ^ { 2 } + a x - b y = 0

C

x2+y2ax+by=0x ^ { 2 } + y ^ { 2 } - a x + b y = 0

D

x2+y2+ax+by=0x ^ { 2 } + y ^ { 2 } + a x + b y = 0

Answer

x2+y2axby=0x ^ { 2 } + y ^ { 2 } - a x - b y = 0

Explanation

Solution

Required equation is (xa)x+(yb)y=0( x - a ) x + ( y - b ) y = 0 or

x2ax+y2by=0x ^ { 2 } - a x + y ^ { 2 } - b y = 0 .