Question

The equation of the circle which passes through (1, 0) and

(0, 1) and has its radius as small as possible, is.

• A. $x ^ { 2 } + y ^ { 2 } - 2 x - 2 y + 1 = 0$
• B. $x ^ { 2 } + y ^ { 2 } - x - y = 0$
• C. $2 x ^ { 2 } + 2 y ^ { 2 } - 3 x - 3 y + 1 = 0$
• D. $x ^ { 2 } + y ^ { 2 } - 3 x - 3 y + 2 = 0$

Answer 1

Answer: (B)

$x ^ { 2 } + y ^ { 2 } - x - y = 0$

Answer 2

The radius will be minimum, if the given points are the end points of a diameter.