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Question

Question: The equation of the circle touching \(x = 0 , y = 0\) and \(x = 4\) is....

The equation of the circle touching x=0,y=0x = 0 , y = 0 and x=4x = 4 is.

A

x2+y24x4y+16=0x ^ { 2 } + y ^ { 2 } - 4 x - 4 y + 16 = 0

B

x2+y28x8y+16=0x ^ { 2 } + y ^ { 2 } - 8 x - 8 y + 16 = 0

C

x2+y2+4x+4y+4=0x ^ { 2 } + y ^ { 2 } + 4 x + 4 y + 4 = 0

D

x2+y24x4y+4=0x ^ { 2 } + y ^ { 2 } - 4 x - 4 y + 4 = 0

Answer

x2+y24x4y+4=0x ^ { 2 } + y ^ { 2 } - 4 x - 4 y + 4 = 0

Explanation

Solution

(x2)2+(y2)2=4( x - 2 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 4

x2+44x+y2+44y=4x ^ { 2 } + 4 - 4 x + y ^ { 2 } + 4 - 4 y = 4

x2+y24x4y+4=0x ^ { 2 } + y ^ { 2 } - 4 x - 4 y + 4 = 0 .