Question

The equation of the circle passing through the point (–2, 4) and through the points of intersection of the circle

x² + y² – 2x – 6y + 6=0 and the line 3x + 2y – 5 = 0, is -

• A. x² + y² + 2x – 4y – 4 = 0
• B. x² + y² + 4x – 2y – 4 = 0
• C. x² + y² – 3x – 4y = 0
• D. x² + y² – 4x – 2y = 0

Answer 1

Answer: (B)

x² + y² + 4x – 2y – 4 = 0

Answer 2

Required equation circle

(x² + y² – 2x – 6y + 6) + l (3x + 2y – 5) = 0

This circle passing through point (–2, 4)

\ (4 + 16 + 4 – 24 + 6) + l (–6 + 8 – 5) = 0 Ю l = 2

\ Circle x² + y² + 4x – 2y – 4 = 0