Question
Question: The equation of the circle passing through the point (0, 0) and the points where the straight line 3...
The equation of the circle passing through the point (0, 0) and the points where the straight line 3x + 4y = 12, meets the axes of coordinates, is –
A
x2 + y2 + 4x – 3y = 0
B
x2 + y2 – 4x – 3y = 0
C
x2 + y2 – 4x + 3y = 0
D
None of these
Answer
x2 + y2 – 4x – 3y = 0
Explanation
Solution
3x + 4y = 12
Ž 4x+ 3y= 1
A(4, 0), B(0, 3)
AB = Diameter Equation
(x – 4) (x – 0) + (y – 0) (y – 3) = 0