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Question: The equation of the circle passing through the point (0, 0) and the points where the straight line 3...

The equation of the circle passing through the point (0, 0) and the points where the straight line 3x + 4y = 12, meets the axes of coordinates, is –

A

x2 + y2 + 4x – 3y = 0

B

x2 + y2 – 4x – 3y = 0

C

x2 + y2 – 4x + 3y = 0

D

None of these

Answer

x2 + y2 – 4x – 3y = 0

Explanation

Solution

3x + 4y = 12

Ž x4\frac{x}{4}+ y3\frac{y}{3}= 1

A(4, 0), B(0, 3)

AB = Diameter Equation

(x – 4) (x – 0) + (y – 0) (y – 3) = 0