Question
Question: The equation of the circle passing through the point (2, 1) and touching y-axis at the origin is....
The equation of the circle passing through the point (2, 1) and touching y-axis at the origin is.
A
x2+y2−5x=0
B
2x2+2y2−5x=0
C
x2+y2+5x=0
D
None of these
Answer
2x2+2y2−5x=0
Explanation
Solution
We have the equation of circle
x2+y2+2gx+2fy+c=0

But it passes through (0, 0) and (2, 1), then
c=0 ….(i)
5+4g+2f=0 ….(ii)
Also g2+f2−c=∣g∣ ⇒ f=0 {∵c=0}
From (ii), g=−45
Hence the equation will be 2x2+2y2−5x=0 .