Question
Question: The equation of the circle passing through the points (0, 0), (0, b) and (a, b) is....
The equation of the circle passing through the points (0, 0), (0, b) and (a, b) is.
A
x2+y2+ax+by=0
B
x2+y2−ax+by=0
C
x2+y2−ax−by=0
D
x2+y2+ax−by=0
Answer
x2+y2−ax−by=0
Explanation
Solution
Equation of circle passing through (0, 0) is
x2+y2+2gx+2fy=0 ….(i)
Also, circle (i) is passing through (0, b) and (a, b)
∴ f=−2b and a2+b2+2ag+2(−2b)b=0
⇒g=−2a
Hence the equations of circle is, x2+y2−ax−by=0.