Solveeit Logo

Question

Question: The equation of the circle passing through (1, 0) and (0, 1) and having smallest possible radius is-...

The equation of the circle passing through (1, 0) and (0, 1) and having smallest possible radius is-

A

x2 + y2 – x – y = 0

B

x2 + y2 + x + y = 0

C

x2 + y2 – 2x – y = 0

D

x2 + y2 – x – 2y = 0

Answer

x2 + y2 – x – y = 0

Explanation

Solution

A(1, 0), B(0, 1)

AB will be diameter of circle

Ž Equation (x – 1) (x – 0) + (y – 0) (y – 1) = 0