Question
Question: The equation of the circle passing through (1, 0) and (0, 1) and having smallest possible radius is-...
The equation of the circle passing through (1, 0) and (0, 1) and having smallest possible radius is-
A
x2 + y2 – x – y = 0
B
x2 + y2 + x + y = 0
C
x2 + y2 – 2x – y = 0
D
x2 + y2 – x – 2y = 0
Answer
x2 + y2 – x – y = 0
Explanation
Solution
A(1, 0), B(0, 1)
AB will be diameter of circle
Ž Equation (x – 1) (x – 0) + (y – 0) (y – 1) = 0