Question
Question: The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is....
The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is.
A
(x−5)2+(y+5)2=25
B
(x+4)2+(y+4)2=25
C
(x+6)2+(y+6)2=25
D
(x+5)2+(y+5)2=25
Answer
(x+5)2+(y+5)2=25
Explanation
Solution
Since circle touches the co-ordinate axes in III quadrant.

∴ Radius =−h=−k . Hence h=k=−5
∴ Equation of circle is (x+5)2+(y+5)2=25