Question
Question: The equation of the circle in the first quadrant which touches each axis at a distance 5 from the or...
The equation of the circle in the first quadrant which touches each axis at a distance 5 from the origin is –
A
x2 + y2 + 5x + 5y + 25 = 0
B
x2 + y2 – 10x – 10y + 25 = 0
C
x2 + y2 – 5x – 5y + 25 = 0
D
x2 + y2 + 10x + 10y + 25 = 0
Answer
x2 + y2 – 10x – 10y + 25 = 0
Explanation
Solution
r = 5
Centre (5, 5)
(x – 5)2 + (y – 5)2 = 25