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Question

Question: The equation of the circle in the first quadrant which touches each axis at a distance 5 from the or...

The equation of the circle in the first quadrant which touches each axis at a distance 5 from the origin is –

A

x2 + y2 + 5x + 5y + 25 = 0

B

x2 + y2 – 10x – 10y + 25 = 0

C

x2 + y2 – 5x – 5y + 25 = 0

D

x2 + y2 + 10x + 10y + 25 = 0

Answer

x2 + y2 – 10x – 10y + 25 = 0

Explanation

Solution

r = 5

Centre (5, 5)

(x – 5)2 + (y – 5)2 = 25