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Question

Question: The equation of the circle in the first quadrant touching each coordinate axis at a distance of one ...

The equation of the circle in the first quadrant touching each coordinate axis at a distance of one unit from the origin is.

A

x2+y22x2y+1=0x ^ { 2 } + y ^ { 2 } - 2 x - 2 y + 1 = 0

B

x2+y22x2y1=0x ^ { 2 } + y ^ { 2 } - 2 x - 2 y - 1 = 0

C

x2+y22x2y=0x ^ { 2 } + y ^ { 2 } - 2 x - 2 y = 0

D

None of these

Answer

x2+y22x2y+1=0x ^ { 2 } + y ^ { 2 } - 2 x - 2 y + 1 = 0

Explanation

Solution

Circle is x2+y22x2y+1=0x ^ { 2 } + y ^ { 2 } - 2 x - 2 y + 1 = 0as centre is (1, 1) and radius = 1.