Question
Question: The equation of the circle in the first quadrant touching each coordinate axis at a distance of one ...
The equation of the circle in the first quadrant touching each coordinate axis at a distance of one unit from the origin is.
A
x2+y2−2x−2y+1=0
B
x2+y2−2x−2y−1=0
C
x2+y2−2x−2y=0
D
None of these
Answer
x2+y2−2x−2y+1=0
Explanation
Solution
Circle is x2+y2−2x−2y+1=0as centre is (1, 1) and radius = 1.