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Question: The equation of the chord of the hyperbola $25x^2 - 16y^2 = 400$ that is bisected at point (5, 3) is...

The equation of the chord of the hyperbola 25x216y2=40025x^2 - 16y^2 = 400 that is bisected at point (5, 3) is :

A

135x48y=481135x - 48y = 481

B

125x48y=481125x - 48y = 481

C

125x4y=48125x - 4y = 48

D

None of these

Answer

125x48y=481125x - 48y = 481

Explanation

Solution

Let the equation of the hyperbola be S:25x216y2=400S: 25x^2 - 16y^2 = 400. The point of bisection of the chord is (x1,y1)=(5,3)(x_1, y_1) = (5, 3).

The equation of the chord of a conic section S=0S=0 that is bisected at the point (x1,y1)(x_1, y_1) is given by the formula T=S1T = S_1. Here, S=25x216y2400S = 25x^2 - 16y^2 - 400.

TT is obtained by replacing x2x^2 with xx1xx_1 and y2y^2 with yy1yy_1 in the terms involving x2x^2 and y2y^2, and keeping the constant term as is. T=25xx116yy1400T = 25xx_1 - 16yy_1 - 400.

S1S_1 is obtained by substituting the coordinates (x1,y1)(x_1, y_1) into the equation SS. S1=25x1216y12400S_1 = 25x_1^2 - 16y_1^2 - 400.

The equation of the chord is T=S1T = S_1: 25xx116yy1400=25x1216y1240025xx_1 - 16yy_1 - 400 = 25x_1^2 - 16y_1^2 - 400 25xx116yy1=25x1216y1225xx_1 - 16yy_1 = 25x_1^2 - 16y_1^2

Substitute the given point (x1,y1)=(5,3)(x_1, y_1) = (5, 3): 25x(5)16y(3)=25(5)216(3)225x(5) - 16y(3) = 25(5)^2 - 16(3)^2 125x48y=25(25)16(9)125x - 48y = 25(25) - 16(9) 125x48y=625144125x - 48y = 625 - 144 125x48y=481125x - 48y = 481