Question
Question: The equation of the chord of the hyperbola $25x^2 - 16y^2 = 400$ that is bisected at point (5, 3) is...
The equation of the chord of the hyperbola 25x2−16y2=400 that is bisected at point (5, 3) is :

135x−48y=481
125x−48y=481
125x−4y=48
None of these
125x−48y=481
Solution
Let the equation of the hyperbola be S:25x2−16y2=400. The point of bisection of the chord is (x1,y1)=(5,3).
The equation of the chord of a conic section S=0 that is bisected at the point (x1,y1) is given by the formula T=S1. Here, S=25x2−16y2−400.
T is obtained by replacing x2 with xx1 and y2 with yy1 in the terms involving x2 and y2, and keeping the constant term as is. T=25xx1−16yy1−400.
S1 is obtained by substituting the coordinates (x1,y1) into the equation S. S1=25x12−16y12−400.
The equation of the chord is T=S1: 25xx1−16yy1−400=25x12−16y12−400 25xx1−16yy1=25x12−16y12
Substitute the given point (x1,y1)=(5,3): 25x(5)−16y(3)=25(5)2−16(3)2 125x−48y=25(25)−16(9) 125x−48y=625−144 125x−48y=481