Question
Question: The equation of the chord of contact of tangents drawn from a point (2, –1) to the hyperbola\(2x^{2}...
The equation of the chord of contact of tangents drawn from a point (2, –1) to the hyperbola2x2+5xy+2y2+4x+5y+2=0 is
A
32x+9y=144
B
32x+9y=55
C
32x+9y+144=0
D
32x+9y+55=0
Answer
32x+9y=144
Explanation
Solution
From T=0 i.e., a2xx1−b2yy1=1. Here, 16x2−9y2=144 i.e., 9x2−16y2=1
So, the equation of chord of contact of tangents drawn from a point (2, –) to the hyperbola is 92x−16(−1)y=1
i.e., 32x+9y=144