Solveeit Logo

Question

Question: The equation of the chord of contact of tangents drawn from a point (2, –1) to the hyperbola\(2x^{2}...

The equation of the chord of contact of tangents drawn from a point (2, –1) to the hyperbola2x2+5xy+2y2+4x+5y+2=02x^{2} + 5xy + 2y^{2} + 4x + 5y + 2 = 0 is

A

32x+9y=14432x + 9y = 144

B

32x+9y=5532x + 9y = 55

C

32x+9y+144=032x + 9y + 144 = 0

D

32x+9y+55=032x + 9y + 55 = 0

Answer

32x+9y=14432x + 9y = 144

Explanation

Solution

From T=0T = 0 i.e., xx1a2yy1b2=1\frac{xx_{1}}{a^{2}} - \frac{yy_{1}}{b^{2}} = 1. Here, 16x29y2=14416x^{2} - 9y^{2} = 144 i.e., x29y216=1\frac{x^{2}}{9} - \frac{y^{2}}{16} = 1

So, the equation of chord of contact of tangents drawn from a point (2, –) to the hyperbola is 2x9(1)y16=1\frac{2x}{9} - \frac{( - 1)y}{16} = 1

i.e., 32x+9y=14432x + 9y = 144