Question
Question: The equation of the chord joining two points (x<sub>1</sub>, y<sub>1</sub>) and (x<sub>2</sub>, y<su...
The equation of the chord joining two points (x1, y1) and (x2, y2) on the rectangular hyperbola xy = c2 is:
A
x1+x2x+y1+y2y=1
B
x1−x2x+y1−y2y=1
C
y1+y2x+x1+x2y=1
D
y1−y2x+x1−x2y=1
Answer
x1+x2x+y1+y2y=1
Explanation
Solution
The mid point of the chord is (2x1+x2,2y1+y2).
The equation of the chord in terms of its mid point is T = S'
x(2y1+y2)+y(2x1+x2)=2(2x1+x2)(2y1+y2)
⇒ x(y1 + y2) + y(x1 + x2) = (x1 + x2) (y1 + y2)
⇒ x1+x2x+y1+y2y=1.