Solveeit Logo

Question

Question: The equation of the bisectors of the angles between the lines represented by \(x^{2} + 2xy\cot\theta...

The equation of the bisectors of the angles between the lines represented by x2+2xycotθ+y2=0x^{2} + 2xy\cot\theta + y^{2} = 0 is

A

x2y2=0x^{2} - y^{2} = 0

B

x2y2=xyx^{2} - y^{2} = xy

C

(x2y2)cotθ=2xy(x^{2} - y^{2})\cot\theta = 2xy

D

None of these

Answer

x2y2=0x^{2} - y^{2} = 0

Explanation

Solution

Equation of bisectors is given by x2y2ab=xyh\frac{x^{2} - y^{2}}{a - b} = \frac{xy}{h}

or x2y20=xycotθ\frac{x^{2} - y^{2}}{0} = \frac{xy}{\cot\theta}x2y2=0x^{2} - y^{2} = 0