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Question: The equation of the bisectors of the angles between the lines ![](https://cdn.pureessence.tech/canva...

The equation of the bisectors of the angles between the lines are

A

y=±xy = \pm x andx=0x = 0

B

x=12x = \frac { 1 } { 2 } and y=12y = \frac { 1 } { 2 }

C

y=0y = 0andx=0x = 0

D

None of these

Answer

y=0y = 0andx=0x = 0

Explanation

Solution

The equation of lines are x+y=0x + y = 0 and xy=0x - y = 0 .

\therefore The equation of bisectors of the angles between these lines are x+y1+1=±xy1+1\frac { x + y } { \sqrt { 1 + 1 } } = \pm \frac { x - y } { \sqrt { 1 + 1 } }x+y=±(xy)x + y = \pm ( x - y )

Taking +ve sign, we get y=0y = 0; Taking –ve sign, we get y=0y = 0.