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Question: The equation of the bisectors of angle between the lines represented by equation \((y - mx)^{2} = (x...

The equation of the bisectors of angle between the lines represented by equation (ymx)2=(x+my)2(y - mx)^{2} = (x + my)^{2}is

A

mx2+(m21)xymy2=0mx^{2} + (m^{2} - 1)xy - my^{2} = 0

B

mx2(m21)xymy2=0mx^{2} - (m^{2} - 1)xy - my^{2} = 0

C

mx2+(m21)xy+my2=0mx^{2} + (m^{2} - 1)xy + my^{2} = 0

D

None of these

Answer

mx2+(m21)xymy2=0mx^{2} + (m^{2} - 1)xy - my^{2} = 0

Explanation

Solution

The equation is

y2+m2x22mxyx2m2y22mxy=0y^{2} + m^{2}x^{2} - 2mxy - x^{2} - m^{2}y^{2} - 2mxy = 0

x2(m21)+y2(1m2)4mxy=0\Rightarrow x^{2}(m^{2} - 1) + y^{2}(1 - m^{2}) - 4mxy = 0

Therefore, the equation of bisectors is x2y2xy\frac{x^{2} - y^{2}}{xy}

=(m21)(1m2)2mmx2+(m21)xymy2=0= \frac{(m^{2} - 1) - (1 - m^{2})}{- 2m} \Rightarrow mx^{2} + (m^{2} - 1)xy - my^{2} = 0.