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Question

Mathematics Question on Coordinate Geometry

The equation of straight line which passes through the point (a cos3θ, a sin3θ) and perpendicular to x secθ+y cosecθ = a is

A

xa+yb=a cosθ\frac{x}{a}+\frac{y}{b}=a\ \cos\theta

B

x cosθ - y sinθ = a cos2θ

C

x cosθ + y sinθ = a cos2θ

D

x cosθ - y sinθ = -a cos2θ

Answer

x cosθ - y sinθ = a cos2θ

Explanation

Solution

The correct answer is () :