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Question

Question: The equation of straight line passing through point of intersection of the straight lines \(3 x - y ...

The equation of straight line passing through point of intersection of the straight lines 3xy+2=03 x - y + 2 = 0 and 5x2y+7=05 x - 2 y + 7 = 0 and having infinite slope is

A

x=2x = 2

B

x+y=3x + y = 3

C

x=3x = 3

D

x=4x = 4

Answer

x=3x = 3

Explanation

Solution

Required line should be, (3xy+2)+λ(5x2y+7)=0( 3 x - y + 2 ) + \lambda ( 5 x - 2 y + 7 ) = 0.....(i)

(3+5λ)x(2λ+1)y+(2+7λ)=0( 3 + 5 \lambda ) x - ( 2 \lambda + 1 ) y + ( 2 + 7 \lambda ) = 0

y=(3+5λ2λ+1)x+2+7λ2λ+1y = \left( \frac { 3 + 5 \lambda } { 2 \lambda + 1 } \right) x + \frac { 2 + 7 \lambda } { 2 \lambda + 1 } ......(ii)

As the equation (ii) has infinite slope, 2λ+1=02 \lambda + 1 = 0λ=12\lambda = \frac { - 1 } { 2 }

Putting λ=12\lambda = \frac { - 1 } { 2 } in equation (i), We have

(3xy+2)+(12)(5x2y+7)=0( 3 x - y + 2 ) + \left( \frac { - 1 } { 2 } \right) ( 5 x - 2 y + 7 ) = 0x=3x = 3