Question: The equation of stationary wave along a stretched string is given by y = 5 sin $\frac{\pi x}{3}$co...

Question

The equation of stationary wave along a stretched string is given by y = 5 sin $\frac{\pi x}{3}$ cos 40 p t Where x and y are in cm and t in second. The separation between two adjacent nodes is–

Answer 1

Solution

y = 5 sin $\frac{\pi}{3}$ x cos 40p t

k = $\frac{2\pi}{\lambda}$ = $\frac{\pi}{3}$ ̃ l = 6 cm

d = $\frac{\lambda}{2}$ = 3 cm

Question: The equation of stationary wave along a stretched string is given by y = 5 sin \(\frac{\pi x}{3}\)co...

Solution