Question
Physics Question on Waves
The equation of stationary wave along a stretched string is given by y=5sin3πxcos40πt, where, x and y are in cm and t in second. The separation between two adjacent nodes is :
A
1. 5 cm
B
3 cm
C
6 cm
D
4 cm
Answer
3 cm
Explanation
Solution
Given, equation
y=5sin3πxcos40πt
Comparing with standard equation
y=Asinkxcosωt
∴k=3π
⇒λ2π=3π
λ=6cm
Separation between two consecutive nodes
=2λ=26=3cm