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Question: The equation of state of some gases can be expressed as \(\left( P + \frac{a}{V^{2}} \right)(V - b) ...

The equation of state of some gases can be expressed as (P+aV2)(Vb)=RT\left( P + \frac{a}{V^{2}} \right)(V - b) = RT. Here PP is the pressure, VV is the volume, TT is the absolute temperature and a,b,Ra,b,R are constants. The dimensions of a'a' are

A

ML5T2ML^{5}T^{- 2}

B

ML1T2ML^{- 1}T^{- 2}

C

M0L3T0M^{0}L^{3}T^{0}

D

M0L6T0M^{0}L^{6}T^{0}

Answer

ML5T2ML^{5}T^{- 2}

Explanation

Solution

By principle of dimensional homogenity

[aV2]=[P]\left\lbrack \frac{a}{V^{2}} \right\rbrack = \lbrack P\rbrack

\therefore [a]=[P]6mu[V2]=[ML1T2]6mu×[L6]\lbrack a\rbrack = \lbrack P\rbrack\mspace{6mu}\lbrack V^{2}\rbrack = \lbrack ML^{- 1}T^{- 2}\rbrack\mspace{6mu} \times \lbrack L^{6}\rbrack = [ML5T2]\lbrack ML^{5}T^{- 2}\rbrack