Question

The equation of state of a gas is given by $\left( P + \frac{aT^{2}}{V} \right)$V^c = (RT + b), where a,b,c and R are constants. The isotherms can be represented by P = AV^m – BVⁿ, where A and B depend only on temperature and –

• A. m = –c and n = –1
• B. m = c and n = 1
• C. m = –c and n = 1
• D. m = c and n = –1

Answer 1

Answer: (A)

m = –c and n = –1

Answer 2

$\left( P + \frac{aT^{2}}{V} \right)$V^c = (RT + b)

̃ P = (RT + b)V^–c – (aT²)V^–1

Comparing this equation with P = AV^m–BVⁿ

we get m = – c and n = –1.