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Question

Question: The equation of state corresponding to 8g of \(O_{2}\) is...

The equation of state corresponding to 8g of O2O_{2} is

A

PV=8RTPV = 8RT

B

PV=RT/4PV = RT/4

C

PV=RTPV = RT

D

PV=RT/2PV = RT/2

Answer

PV=RT/4PV = RT/4

Explanation

Solution

As 32 gm O2O_{2} means 1 mole therefore 8 gm O2O_{2} means 1 / 4mole i.e. μ=14\mu = \frac{1}{4}

So from PV=μRTPV = \mu RT we get PV=14RTPV = \frac{1}{4}RT or PV=RT4PV = \frac{RT}{4}