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Question

Question: The equation of pair of straight lines joining the point of intersection of the curve \(x^{2} + y^{2...

The equation of pair of straight lines joining the point of intersection of the curve x2+y2=4x^{2} + y^{2} = 4 and yx=2y - x = 2 to the origin, is

A

x2+y2=(yx)2x^{2} + y^{2} = (y - x)^{2}

B

x2+y2+(yx)2=0x^{2} + y^{2} + (y - x)^{2} = 0

C

x2+y2=4(yx)2x^{2} + y^{2} = 4(y - x)^{2}

D

x2+y2+4(yx)2=0x^{2} + y^{2} + 4(y - x)^{2} = 0

Answer

x2+y2=(yx)2x^{2} + y^{2} = (y - x)^{2}

Explanation

Solution

Equation can be found by homogenising the curve w.r.t. line.

i.e., x2+y2=4(yx2)2x^{2} + y^{2} = 4\left( \frac{y - x}{2} \right)^{2}or x2+y2=(yx)2x^{2} + y^{2} = (y - x)^{2}.