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Question

Question: The equation of normal at the point \(y ^ { 2 } = 4 a x\), is...

The equation of normal at the point y2=4axy ^ { 2 } = 4 a x, is

A

4x+8y+9a=04 x + 8 y + 9 a = 0

B

4x+8y9a=04 x + 8 y - 9 a = 0

C

4x+ya=04 x + y - a = 0

D

4xy+a=04 x - y + a = 0

Answer

4x+8y9a=04 x + 8 y - 9 a = 0

Explanation

Solution

From yy1=y12a(xx1)y - y _ { 1 } = - \frac { - y _ { 1 } } { 2 a } \left( x - x _ { 1 } \right)

ya=a2a(xa4)y - a = \frac { - a } { 2 a } \left( x - \frac { a } { 4 } \right)2y+x9a4=02 y + x - \frac { 9 a } { 4 } = 04x+8y9a=04 x + 8 y - 9 a = 0