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Question: The equation of line whose mid point is \(\left( x _ { 1 } , y _ { 1 } \right)\) in between the axes...

The equation of line whose mid point is (x1,y1)\left( x _ { 1 } , y _ { 1 } \right) in between the axes, is.

A

xx1+yy1=2\frac { x } { x _ { 1 } } + \frac { y } { y _ { 1 } } = 2

B

xx1+yy1=12\frac { x } { x _ { 1 } } + \frac { y } { y _ { 1 } } = \frac { 1 } { 2 }

C

xx1+yy1=1\frac { x } { x _ { 1 } } + \frac { y } { y _ { 1 } } = 1

D

None of these

Answer

xx1+yy1=2\frac { x } { x _ { 1 } } + \frac { y } { y _ { 1 } } = 2

Explanation

Solution

Intersection point on x-axis is (2x1,0)\left( 2 x _ { 1 } , 0 \right) and on y-axis is (0,2y1)\left( 0,2 y _ { 1 } \right). Thus equation of line passes through these points is xx1+yy1=2\frac { x } { x _ { 1 } } + \frac { y } { y _ { 1 } } = 2.