Question
Question: The equation of line, which bisect the line joining two points (2, – 19) and (6, 1) and perpendicula...
The equation of line, which bisect the line joining two points (2, – 19) and (6, 1) and perpendicular to the line joining two points (– 1, 3) and (5, – 1), is.
A
3x−2y=30
B
2x−y−3=0
C
2x+3y=20
D
None of these
Answer
3x−2y=30
Explanation
Solution
Mid point Slope =−1−53+1−1=23
Hence the required line is 3x−2y=30.