Solveeit Logo

Question

Question: The equation of line, which bisect the line joining two points (2, – 19) and (6, 1) and perpendicula...

The equation of line, which bisect the line joining two points (2, – 19) and (6, 1) and perpendicular to the line joining two points (– 1, 3) and (5, – 1), is.

A

3x2y=303 x - 2 y = 30

B

2xy3=02 x - y - 3 = 0

C

2x+3y=202 x + 3 y = 20

D

None of these

Answer

3x2y=303 x - 2 y = 30

Explanation

Solution

Mid point Slope =13+115=32= \frac { - 1 } { \frac { 3 + 1 } { - 1 - 5 } } = \frac { 3 } { 2 }

Hence the required line is 3x2y=303 x - 2 y = 30.