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Question: The equation of line passing through the point of intersection of the lines \(4 x - 3 y - 1 = 0\) a...

The equation of line passing through the point of intersection of the lines 4x3y1=04 x - 3 y - 1 = 0 and 5x2y3=05 x - 2 y - 3 = 0 and parallel to the line is.

A

x3y=1x - 3 y = 1

B

3x2y=13 x - 2 y = 1

C

2x3y=12 x - 3 y = 1

D

2xy=12 x - y = 1

Answer

3x2y=13 x - 2 y = 1

Explanation

Solution

The point of intersection of the lines is (1, 1). The equation of line parallel to 2y3x+2=02 y - 3 x + 2 = 0 is 2y3x+k=02 y - 3 x + k = 0. It also passes through (1, 1), therefore k=1k = 1. Hence the required equation is 2y3x+1=02 y - 3 x + 1 = 0 or 3x2y=13 x - 2 y = 1 .