Question

The equation of line passing through point of intersection of lines $3 x - 2 y - 1 = 0$ and $x - 4 y + 3 = 0$ and the point $( \pi , 0 )$ is.

• A. $x - y = \pi$
• B. $x - y = \pi ( y + 1 )$
• C. $x - y = \pi ( 1 - y )$
• D. $x + y = \pi ( 1 - y )$

Answer 1

Answer: (C)

$x - y = \pi ( 1 - y )$

Answer 2

The point of intersection is (1, 1) Therefore the equation of the line passing through (1, 1) and $( \pi , 0 )$ is $y - 1 = \frac { - 1 } { \pi - 1 } ( x - 1 ) \Rightarrow x - y = \pi ( 1 - y )$.