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Question

Question: The equation of line passing through (c, d) and parallel to <img src="https://cdn.pureessence.tech/c...

The equation of line passing through (c, d) and parallel to is.

A

a(x+c)+b(y+d)=0a ( x + c ) + b ( y + d ) = 0

B

a(x+c)b(y+d)=0a ( x + c ) - b ( y + d ) = 0

C

a(xc)+b(yd)=0a ( x - c ) + b ( y - d ) = 0

D

None of these

Answer

a(xc)+b(yd)=0a ( x - c ) + b ( y - d ) = 0

Explanation

Solution

The required equation which passes through (c, d) and its gradient is ab- \frac { a } { b }, is yd=ab(xc)y - d = - \frac { a } { b } ( x - c )

a(xc)+b(yd)=0\Rightarrow a ( x - c ) + b ( y - d ) = 0.