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Question

Question: The equation of directrix of the parabola \[{\left( {y - 2} \right)^2} = 4(x - 4)\] A) \(x + 1 = ...

The equation of directrix of the parabola (y2)2=4(x4){\left( {y - 2} \right)^2} = 4(x - 4)
A) x+1=0x + 1 = 0
B) x=1x = 1
C) x=2x = 2
D) x=5x = 5

Explanation

Solution

In the given question first convert it into the general form of the parabola that is y2=4ax{y^2} = 4ax as we know the equation of this is x=ax = a so let us suppose that the y2=Yy - 2 = Y and x4=Xx - 4 = X equation become Y2=4(1)X{Y^2} = 4\left( 1 \right)X for this the directrix equation is X=1X = 1

Complete step by step solution:
As in the given question we have to find out the equation of directrix of the parabola that is (y2)2=4(x4){\left( {y - 2} \right)^2} = 4(x - 4)
A parabola is the locus of the point in a plane which are an equal distance away from a given point and given line , the given line is known as the directrix of the parabola
In general if the parabola is y2=4ax{y^2} = 4ax then the equation of directrix is x=ax = a So the above equation we to convert it into general form ,
So let us suppose that the y2=Yy - 2 = Y and x4=Xx - 4 = X now put it in into the given equation that is (y2)2=4(x4){\left( {y - 2} \right)^2} = 4(x - 4)
It looks as Y2=4X{Y^2} = 4X or Y2=4(1)X{Y^2} = 4\left( 1 \right)X
Hence on comparing with general equation that is y2=4ax{y^2} = 4ax we get a=1a = 1
So the equation of the directrix of the Y2=4X{Y^2} = 4X is X=1X = 1
We know that the x4=Xx - 4 = X as it is suppose by us now put it in the equation of directrix ,
x4=1x - 4 = 1
on solving we get x=5x = 5 hence it is the required equation of the directrix .

So, the correct answer is “Option D”.

Note: As for the parabola y2=4ax{y^2} = 4ax the axis is x- axis and the y- axis for the given question (y2)2=4(x4){\left( {y - 2} \right)^2} = 4(x - 4) the axis become y=2y = 2 and x=4x = 4 it is shifted parabola and the focus of this parabola is at the coordinate (5,2)\left( {5,2} \right)