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Question: The equation of curve passing through (1, 1) in which the sub-tangent is always bisected at the orig...

The equation of curve passing through (1, 1) in which the sub-tangent is always bisected at the origin is –

A

y2 = x

B

2x2 – y2 = 1

C

x2 + y2 = 2

D

x + y = 2

Answer

y2 = x

Explanation

Solution

TM is sub-tangent where T ≡ (xydxdy,0)\left( x - y \frac { d x } { d y } , 0 \right) and

M ≡ (x, 0)

12\frac { 1 } { 2 } (xydxdy+x)\left( x - y \frac { d x } { d y } + x \right)= 0

⇒ 2x – y = 0 or 2 dyy\int \frac { d y } { y } = dxx\int \frac { \mathrm { dx } } { \mathrm { x } }

2­lny = lncx

y2 = cx

curve passes through (1, 1)

∴ c = 1, y2 = x