Question

The equation of circle whose diameter is the line joining the points (­–4, 3) and (12, –1) is.

• A. $x ^ { 2 } + y ^ { 2 } + 8 x + 2 y + 51 = 0$
• B. $x ^ { 2 } + y ^ { 2 } + 8 x - 2 y - 51 = 0$
• C. $x ^ { 2 } + y ^ { 2 } + 8 x + 2 y - 51 = 0$
• D. $x ^ { 2 } + y ^ { 2 } - 8 x - 2 y - 51 = 0$

Answer 1

Answer: (D)

$x ^ { 2 } + y ^ { 2 } - 8 x - 2 y - 51 = 0$

Answer 2

Required equation is

$\left( x - x _ { 1 } \right) \left( x - x _ { 2 } \right) + \left( y - y _ { 1 } \right) \left( y - y _ { 2 } \right) = 0$

$( x + 4 ) ( x - 12 ) + ( y - 3 ) ( y + 1 ) = 0$ $x ^ { 2 } + y ^ { 2 } - 8 x - 2 y - 51 = 0$ .