Question
Question: The equation of circle passing through the points of intersection of circles x<sup>2</sup>+y<sup>2</...
The equation of circle passing through the points of intersection of circles x2+y2–6x+8 = 0 and x2 + y2 = 6 and point (1,1) is -
A
x2 + y2 – 6x + 4 = 0
B
x2 + y2 – 3x + 1 = 0
C
x2 + y2 – 4y + 2 = 0
D
None of these
Answer
x2 + y2 – 3x + 1 = 0
Explanation
Solution
Required equation is S + lS'= 0
(x2 + y2– 6x+8)+ l (x2+y2– 6)= 0
it passes through (1, 1)
\ (1 + 1 – 6 + 8) + l (1 + 1 – 6) = 0 ή l = 1
\ equation 2x2 + 2y2 – 6x + 2 = 0 ή x2+y2–3x + 1 = 0