Question

The equation of circle passing through (4, 5) and having the centre at (2, 2), is.

• A. $x ^ { 2 } + y ^ { 2 } + 4 x + 4 y - 5 = 0$
• B. $x ^ { 2 } + y ^ { 2 } - 4 x - 4 y - 5 = 0$
• C. $x ^ { 2 } + y ^ { 2 } - 4 x = 13$
• D. $x ^ { 2 } + y ^ { 2 } - 4 x - 4 y + 5 = 0$

Answer 1

Answer: (B)

$x ^ { 2 } + y ^ { 2 } - 4 x - 4 y - 5 = 0$

Answer 2

Centre (2, 2) and

$R = \sqrt { ( 4 - 2 ) ^ { 2 } + ( 5 - 2 ) ^ { 2 } } = \sqrt { 13 }$

Hence required equation is $x ^ { 2 } + y ^ { 2 } - 4 x - 4 y - 5 = 0$ .