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Question: The equation of an alternating current is \(i = 50\sqrt{2} \times \sin 400\pi t\) ampere then the fr...

The equation of an alternating current is i=502×sin400πti = 50\sqrt{2} \times \sin 400\pi t ampere then the frequency and the root mean square of the current are respectively

A

200 Hz, 50 amp

B

400 π Hz, 50250\sqrt{2} amp

C

200 Hz, 50250\sqrt{2}amp

D

50 Hz, 200 amp

Answer

200 Hz, 50 amp

Explanation

Solution

Comparing the given equation with i=i0sinωti = i_{0}\sin\omega t

⇒ ω = 400 π ⇒ 2πν = 400π ⇒ ν = 200 Hz.

Also irms=i02=5022i_{rms} = \frac{i_{0}}{\sqrt{2}} = \frac{50\sqrt{2}}{2}= 50 A.