Question
Physics Question on Conservation of energy
The equation of a wave is y=5sin(t0.04−x4), where x is in cm and t in seconds. The maximum velocity of the particle will be
A
(A) 1 ms-1
B
(B) 2 ms-1
C
(C) 1.5 ms-1
D
(D) 1.25 ms-1
Answer
(D) 1.25 ms-1
Explanation
Solution
Explanation:
Equation of wavey=5sin(t0.04−x4)The standard equation of a wave in the given form isy=asin(ωt−2πxλ)Comparing the given equation with the standard equation, we geta=5 and ω=10.04=25Therefore, maximum velocity of particles of the medium,vmax=aω=5×25=125cms−1=1.25ms−1