Question

The equation of a transverse wave travelling on a rope is given by $y = 10\sin\pi(0.01x - 2.00t)$ where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

• A. 63 cm/sec
• B. 75 cm/s
• C. 100 cm/sec
• D. 121 cm/sec

Answer 1

Answer: (A)

63 cm/sec

Answer 2

Standard eq. of travelling wave y = A sin $(kx - \omega ⥂ ⥂ t)$

By comparing with the given equation y = 10 sin (0.01$\pi x - 2\pi t$)

A = 10 cm, $\omega$ = 2 $\pi$

Maximum particle velocity = A$\omega$ = 2$\pi$ × 10 = 63 cm/sec