Solveeit Logo
Login

Question

Question: The equation of a transverse wave is given by \(y = 10\sin\pi(0.01x - 2t)\) where x and y are in cm ...

The equation of a transverse wave is given by y=10sin⁡π(0.01x−2t)y = 10\sin\pi(0.01x - 2t) where x and y are in cm and t is in second. Its frequency is

A

10sec⁡−110\sec^{- 1}{}

B

2sec⁡−12\sec^{- 1}{}

C

1sec⁡−11\sec^{- 1}{}

D

0.01sec⁡−10.01\sec^{- 1}{}

Answer

1sec⁡−11\sec^{- 1}{}

Explanation

Solution

Comparing with the standard equation,

y=Asin⁡2πλ(vt−x)y = A\sin\frac{2\pi}{\lambda}(vt - x), we have

v=200cm/sec⁡v = 200cm/\sec, λ=200cm;∴\lambda = 200cm;\therefore n=vλ=1n = \frac { v } { \lambda } = 1 sec⁡−1\sec^{- 1}{}