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Question: The equation of a tangent to the ellipse \(\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1\) at a part...

The equation of a tangent to the ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 at a particular point is xayb=2\frac{x}{a} - \frac{y}{b} = \sqrt{2}. Then the eccentric angle of the point is

A

π/4

B

3π/4

C

5π/4

D

7π/4

Answer

7π/4

Explanation

Solution

The equation of tangent at ‘θ’ to the ellipse is

xcosθa+ysinθb=1\frac{x\cos\theta}{a} + \frac{y\sin\theta}{b} = 1

The given tangent is xa(12)+yb(12)\frac{x}{a}\left( \frac{1}{\sqrt{2}} \right) + \frac{y}{b}\left( \frac{- 1}{\sqrt{2}} \right) = 1

∴ Cosθ = 12\frac{1}{\sqrt{2}}, sinθ = -12\frac{1}{\sqrt{2}}

⇒ θ = 7π/4