Question

The equation of a straight line passing through (– 3, 2) and cutting an intercept equal in magnitude but opposite in sign from the axes is given by

• A. $x - y + 5 = 0$
• B. $x + y - 5 = 0$
• C. $x - y - 5 = 0$
• D. $x + y + 5 = 0$

Answer 1

Answer: (A)

$x - y + 5 = 0$

Answer 2

Let the equation be $x - y = a$

But it passes through (–3, 2), hence $a = - 3 - 2 = - 5$.

Hence the equation of straight line is $x - y + 5 = 0$.