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Question: The equation of a straight line drawn through the focus of the parabola y<sup>2</sup> =-4x at an ang...

The equation of a straight line drawn through the focus of the parabola y2 =-4x at an angle of 1200 to the x-axis is

A

y+3(x1)=0y + \sqrt{3}(x - 1) = 0

B

y3(x1)=0y - \sqrt{3}(x - 1) = 0

C

y+3(x+1)=0y + \sqrt{3}(x + 1) = 0

D

y3(x+1)=0y - \sqrt{3}(x + 1) = 0

Answer

y+3(x+1)=0y + \sqrt{3}(x + 1) = 0

Explanation

Solution

m = tan(1200) = 3- \sqrt{3}

= Slope of the line which passes through (-1, 0)

Required equation, y+3(x+1)=0y + \sqrt{3}(x + 1) = 0