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Question

Physics Question on Waves

The equation of a simple harmonic wave is given by y=6Sin2π(2t0.1x)y = 6\, Sin\, 2\pi(2t - 0.1x), where xx and yy are in mmmm and tt is in seconds. The phase difference between two particles 2mm2\, mm apart at any instant is

A

18^\circ

B

36^\circ

C

54^\circ

D

7272^\circ

Answer

7272^\circ

Explanation

Solution

From the given equation k=0.2πk=0.2 \pi 2πλ=0.2π\Rightarrow \,\,\,\, \frac{2 \pi}{\lambda} =0.2 \pi λ=10mm\Rightarrow \,\,\, \lambda =10\, mm Δϕ=2πλΔx=2π10×2=2π5=72\Delta \phi =\frac{2 \pi}{\lambda} \Delta x=\frac{2 \pi}{10} \times 2=\frac{2 \pi}{5}=72^{\circ}