Question

The equation of a simple harmonic wave is given by y = 5 sin (100t – x), where x and y are in meter and time is in second will be

• A. 0.04
• B. 0.01
• C. 1
• D. 5

Answer 1

Answer: (A)

0.04

Answer 2

$y = 5\sin\frac{\pi}{2}(100t - x)$

$y = A\sin(\omega t - kx)$

$\therefore\omega = \frac{2\pi}{T} = \frac{\pi}{2} \times 100$

Or $T = \frac{2}{50} = 0.045$